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4a^2+17a+4=0
a = 4; b = 17; c = +4;
Δ = b2-4ac
Δ = 172-4·4·4
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-15}{2*4}=\frac{-32}{8} =-4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+15}{2*4}=\frac{-2}{8} =-1/4 $
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